Integrand size = 15, antiderivative size = 73 \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\frac {3 \text {arctanh}(\cos (c+b x)) \cos (a-c)}{2 b}-\frac {\cos (a+b x)}{b}-\frac {\cos (a-c) \cot (c+b x) \csc (c+b x)}{2 b}+\frac {\csc (c+b x) \sin (a-c)}{b} \]
3/2*arctanh(cos(b*x+c))*cos(a-c)/b-cos(b*x+a)/b-1/2*cos(a-c)*cot(b*x+c)*cs c(b*x+c)/b+csc(b*x+c)*sin(a-c)/b
Time = 0.39 (sec) , antiderivative size = 71, normalized size of antiderivative = 0.97 \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\frac {12 \text {arctanh}\left (\cos (c)-\sin (c) \tan \left (\frac {b x}{2}\right )\right ) \cos (a-c)+(2 \cos (a-2 c-b x)-5 \cos (a+b x)+\cos (a+2 c+3 b x)) \csc ^2(c+b x)}{4 b} \]
(12*ArcTanh[Cos[c] - Sin[c]*Tan[(b*x)/2]]*Cos[a - c] + (2*Cos[a - 2*c - b* x] - 5*Cos[a + b*x] + Cos[a + 2*c + 3*b*x])*Csc[c + b*x]^2)/(4*b)
Time = 0.65 (sec) , antiderivative size = 86, normalized size of antiderivative = 1.18, number of steps used = 15, number of rules used = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.933, Rules used = {5088, 3042, 3091, 3042, 4257, 5089, 3042, 25, 3086, 24, 5088, 3042, 3118, 4257}
Below are the steps used by Rubi to obtain the solution. The rule number used for the transformation is given above next to the arrow. The rules definitions used are listed below.
| \(\displaystyle \int \cos (a+b x) \cot ^3(b x+c) \, dx\) |
| \(\Big \downarrow \) 5088 |
| \(\displaystyle \cos (a-c) \int \cot ^2(c+b x) \csc (c+b x)dx-\int \cot ^2(c+b x) \sin (a+b x)dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \cos (a-c) \int \sec \left (c+b x-\frac {\pi }{2}\right ) \tan \left (c+b x-\frac {\pi }{2}\right )^2dx-\int \cot ^2(c+b x) \sin (a+b x)dx\) |
| \(\Big \downarrow \) 3091 |
| \(\displaystyle \cos (a-c) \left (-\frac {1}{2} \int \csc (c+b x)dx-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )-\int \cot ^2(c+b x) \sin (a+b x)dx\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle \cos (a-c) \left (-\frac {1}{2} \int \csc (c+b x)dx-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )-\int \cot ^2(c+b x) \sin (a+b x)dx\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle \cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )-\int \cot ^2(c+b x) \sin (a+b x)dx\) |
| \(\Big \downarrow \) 5089 |
| \(\displaystyle -\int \cos (a+b x) \cot (c+b x)dx-\sin (a-c) \int \cot (c+b x) \csc (c+b x)dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\int \cos (a+b x) \cot (c+b x)dx-\sin (a-c) \int -\sec \left (c+b x-\frac {\pi }{2}\right ) \tan \left (c+b x-\frac {\pi }{2}\right )dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )\) |
| \(\Big \downarrow \) 25 |
| \(\displaystyle -\int \cos (a+b x) \cot (c+b x)dx+\sin (a-c) \int \sec \left (\frac {1}{2} (2 c-\pi )+b x\right ) \tan \left (\frac {1}{2} (2 c-\pi )+b x\right )dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )\) |
| \(\Big \downarrow \) 3086 |
| \(\displaystyle -\int \cos (a+b x) \cot (c+b x)dx+\frac {\sin (a-c) \int 1d\csc (c+b x)}{b}+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )\) |
| \(\Big \downarrow \) 24 |
| \(\displaystyle -\int \cos (a+b x) \cot (c+b x)dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )+\frac {\sin (a-c) \csc (b x+c)}{b}\) |
| \(\Big \downarrow \) 5088 |
| \(\displaystyle -\cos (a-c) \int \csc (c+b x)dx+\int \sin (a+b x)dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )+\frac {\sin (a-c) \csc (b x+c)}{b}\) |
| \(\Big \downarrow \) 3042 |
| \(\displaystyle -\cos (a-c) \int \csc (c+b x)dx+\int \sin (a+b x)dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )+\frac {\sin (a-c) \csc (b x+c)}{b}\) |
| \(\Big \downarrow \) 3118 |
| \(\displaystyle -\cos (a-c) \int \csc (c+b x)dx+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )+\frac {\sin (a-c) \csc (b x+c)}{b}-\frac {\cos (a+b x)}{b}\) |
| \(\Big \downarrow \) 4257 |
| \(\displaystyle \frac {\cos (a-c) \text {arctanh}(\cos (b x+c))}{b}+\cos (a-c) \left (\frac {\text {arctanh}(\cos (b x+c))}{2 b}-\frac {\cot (b x+c) \csc (b x+c)}{2 b}\right )+\frac {\sin (a-c) \csc (b x+c)}{b}-\frac {\cos (a+b x)}{b}\) |
(ArcTanh[Cos[c + b*x]]*Cos[a - c])/b - Cos[a + b*x]/b + Cos[a - c]*(ArcTan h[Cos[c + b*x]]/(2*b) - (Cot[c + b*x]*Csc[c + b*x])/(2*b)) + (Csc[c + b*x] *Sin[a - c])/b
3.3.52.3.1 Defintions of rubi rules used
Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^( n_.), x_Symbol] :> Simp[a/f Subst[Int[(a*x)^(m - 1)*(-1 + x^2)^((n - 1)/2 ), x], x, Sec[e + f*x]], x] /; FreeQ[{a, e, f, m}, x] && IntegerQ[(n - 1)/2 ] && !(IntegerQ[m/2] && LtQ[0, m, n + 1])
Int[((a_.)*sec[(e_.) + (f_.)*(x_)])^(m_.)*((b_.)*tan[(e_.) + (f_.)*(x_)])^( n_), x_Symbol] :> Simp[b*(a*Sec[e + f*x])^m*((b*Tan[e + f*x])^(n - 1)/(f*(m + n - 1))), x] - Simp[b^2*((n - 1)/(m + n - 1)) Int[(a*Sec[e + f*x])^m*( b*Tan[e + f*x])^(n - 2), x], x] /; FreeQ[{a, b, e, f, m}, x] && GtQ[n, 1] & & NeQ[m + n - 1, 0] && IntegersQ[2*m, 2*n]
Int[csc[(c_.) + (d_.)*(x_)], x_Symbol] :> Simp[-ArcTanh[Cos[c + d*x]]/d, x] /; FreeQ[{c, d}, x]
Int[Cos[v_]*Cot[w_]^(n_.), x_Symbol] :> -Int[Sin[v]*Cot[w]^(n - 1), x] + Si mp[Cos[v - w] Int[Csc[w]*Cot[w]^(n - 1), x], x] /; GtQ[n, 0] && FreeQ[v - w, x] && NeQ[w, v]
Int[Cot[w_]^(n_.)*Sin[v_], x_Symbol] :> Int[Cos[v]*Cot[w]^(n - 1), x] + Sim p[Sin[v - w] Int[Csc[w]*Cot[w]^(n - 1), x], x] /; GtQ[n, 0] && FreeQ[v - w, x] && NeQ[w, v]
Result contains complex when optimal does not.
Time = 0.40 (sec) , antiderivative size = 179, normalized size of antiderivative = 2.45
| method | result | size |
| risch | \(-\frac {{\mathrm e}^{i \left (x b +a \right )}}{2 b}-\frac {{\mathrm e}^{-i \left (x b +a \right )}}{2 b}-\frac {-3 \,{\mathrm e}^{i \left (3 x b +5 a +2 c \right )}+{\mathrm e}^{i \left (3 x b +3 a +4 c \right )}+{\mathrm e}^{i \left (x b +5 a \right )}-3 \,{\mathrm e}^{i \left (x b +3 a +2 c \right )}}{2 b \left (-{\mathrm e}^{2 i \left (x b +a +c \right )}+{\mathrm e}^{2 i a}\right )^{2}}-\frac {3 \ln \left ({\mathrm e}^{i \left (x b +a \right )}-{\mathrm e}^{i \left (a -c \right )}\right ) \cos \left (a -c \right )}{2 b}+\frac {3 \ln \left ({\mathrm e}^{i \left (x b +a \right )}+{\mathrm e}^{i \left (a -c \right )}\right ) \cos \left (a -c \right )}{2 b}\) | \(179\) |
-1/2*exp(I*(b*x+a))/b-1/2/b*exp(-I*(b*x+a))-1/2/b/(-exp(2*I*(b*x+a+c))+exp (2*I*a))^2*(-3*exp(I*(3*b*x+5*a+2*c))+exp(I*(3*b*x+3*a+4*c))+exp(I*(b*x+5* a))-3*exp(I*(b*x+3*a+2*c)))-3/2*ln(exp(I*(b*x+a))-exp(I*(a-c)))/b*cos(a-c) +3/2*ln(exp(I*(b*x+a))+exp(I*(a-c)))/b*cos(a-c)
Leaf count of result is larger than twice the leaf count of optimal. 385 vs. \(2 (69) = 138\).
Time = 0.27 (sec) , antiderivative size = 385, normalized size of antiderivative = 5.27 \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=-\frac {16 \, \cos \left (b x + a\right )^{3} \cos \left (-2 \, a + 2 \, c\right ) - 4 \, {\left (4 \, \cos \left (b x + a\right )^{2} + 1\right )} \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right ) - 4 \, {\left (\cos \left (-2 \, a + 2 \, c\right ) + 5\right )} \cos \left (b x + a\right ) + \frac {3 \, \sqrt {2} {\left (2 \, {\left (\cos \left (-2 \, a + 2 \, c\right ) + 1\right )} \cos \left (b x + a\right ) \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right ) - 2 \, {\left (\cos \left (-2 \, a + 2 \, c\right )^{2} + \cos \left (-2 \, a + 2 \, c\right )\right )} \cos \left (b x + a\right )^{2} + \cos \left (-2 \, a + 2 \, c\right )^{2} + 2 \, \cos \left (-2 \, a + 2 \, c\right ) + 1\right )} \log \left (\frac {2 \, \cos \left (b x + a\right )^{2} \cos \left (-2 \, a + 2 \, c\right ) - 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right ) + \frac {2 \, \sqrt {2} {\left ({\left (\cos \left (-2 \, a + 2 \, c\right ) + 1\right )} \cos \left (b x + a\right ) - \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right )\right )}}{\sqrt {\cos \left (-2 \, a + 2 \, c\right ) + 1}} - \cos \left (-2 \, a + 2 \, c\right ) + 3}{2 \, \cos \left (b x + a\right )^{2} \cos \left (-2 \, a + 2 \, c\right ) - 2 \, \cos \left (b x + a\right ) \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right ) - \cos \left (-2 \, a + 2 \, c\right ) - 1}\right )}{\sqrt {\cos \left (-2 \, a + 2 \, c\right ) + 1}}}{8 \, {\left (2 \, b \cos \left (b x + a\right )^{2} \cos \left (-2 \, a + 2 \, c\right ) - 2 \, b \cos \left (b x + a\right ) \sin \left (b x + a\right ) \sin \left (-2 \, a + 2 \, c\right ) - b \cos \left (-2 \, a + 2 \, c\right ) - b\right )}} \]
-1/8*(16*cos(b*x + a)^3*cos(-2*a + 2*c) - 4*(4*cos(b*x + a)^2 + 1)*sin(b*x + a)*sin(-2*a + 2*c) - 4*(cos(-2*a + 2*c) + 5)*cos(b*x + a) + 3*sqrt(2)*( 2*(cos(-2*a + 2*c) + 1)*cos(b*x + a)*sin(b*x + a)*sin(-2*a + 2*c) - 2*(cos (-2*a + 2*c)^2 + cos(-2*a + 2*c))*cos(b*x + a)^2 + cos(-2*a + 2*c)^2 + 2*c os(-2*a + 2*c) + 1)*log((2*cos(b*x + a)^2*cos(-2*a + 2*c) - 2*cos(b*x + a) *sin(b*x + a)*sin(-2*a + 2*c) + 2*sqrt(2)*((cos(-2*a + 2*c) + 1)*cos(b*x + a) - sin(b*x + a)*sin(-2*a + 2*c))/sqrt(cos(-2*a + 2*c) + 1) - cos(-2*a + 2*c) + 3)/(2*cos(b*x + a)^2*cos(-2*a + 2*c) - 2*cos(b*x + a)*sin(b*x + a) *sin(-2*a + 2*c) - cos(-2*a + 2*c) - 1))/sqrt(cos(-2*a + 2*c) + 1))/(2*b*c os(b*x + a)^2*cos(-2*a + 2*c) - 2*b*cos(b*x + a)*sin(b*x + a)*sin(-2*a + 2 *c) - b*cos(-2*a + 2*c) - b)
\[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\int \cos {\left (a + b x \right )} \cot ^{3}{\left (b x + c \right )}\, dx \]
Leaf count of result is larger than twice the leaf count of optimal. 1254 vs. \(2 (69) = 138\).
Time = 0.25 (sec) , antiderivative size = 1254, normalized size of antiderivative = 17.18 \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\text {Too large to display} \]
-1/4*(2*(cos(5*b*x + a + 4*c) - 2*cos(3*b*x + a + 2*c) + cos(b*x + a))*cos (6*b*x + 2*a + 4*c) - 2*(5*cos(4*b*x + 2*a + 2*c) - 2*cos(4*b*x + 4*c) - 2 *cos(2*b*x + 2*a) + 5*cos(2*b*x + 2*c) - 1)*cos(5*b*x + a + 4*c) + 10*(2*c os(3*b*x + a + 2*c) - cos(b*x + a))*cos(4*b*x + 2*a + 2*c) - 4*(2*cos(3*b* x + a + 2*c) - cos(b*x + a))*cos(4*b*x + 4*c) - 4*(2*cos(2*b*x + 2*a) - 5* cos(2*b*x + 2*c) + 1)*cos(3*b*x + a + 2*c) + 4*cos(2*b*x + 2*a)*cos(b*x + a) - 10*cos(2*b*x + 2*c)*cos(b*x + a) - 3*(cos(5*b*x + a + 4*c)^2*cos(-a + c) + 4*cos(3*b*x + a + 2*c)^2*cos(-a + c) - 4*cos(3*b*x + a + 2*c)*cos(b* x + a)*cos(-a + c) + cos(b*x + a)^2*cos(-a + c) + cos(-a + c)*sin(5*b*x + a + 4*c)^2 + 4*cos(-a + c)*sin(3*b*x + a + 2*c)^2 - 4*cos(-a + c)*sin(3*b* x + a + 2*c)*sin(b*x + a) + cos(-a + c)*sin(b*x + a)^2 - 2*(2*cos(3*b*x + a + 2*c)*cos(-a + c) - cos(b*x + a)*cos(-a + c))*cos(5*b*x + a + 4*c) - 2* (2*cos(-a + c)*sin(3*b*x + a + 2*c) - cos(-a + c)*sin(b*x + a))*sin(5*b*x + a + 4*c))*log(cos(b*x)^2 + 2*cos(b*x)*cos(c) + cos(c)^2 + sin(b*x)^2 - 2 *sin(b*x)*sin(c) + sin(c)^2) + 3*(cos(5*b*x + a + 4*c)^2*cos(-a + c) + 4*c os(3*b*x + a + 2*c)^2*cos(-a + c) - 4*cos(3*b*x + a + 2*c)*cos(b*x + a)*co s(-a + c) + cos(b*x + a)^2*cos(-a + c) + cos(-a + c)*sin(5*b*x + a + 4*c)^ 2 + 4*cos(-a + c)*sin(3*b*x + a + 2*c)^2 - 4*cos(-a + c)*sin(3*b*x + a + 2 *c)*sin(b*x + a) + cos(-a + c)*sin(b*x + a)^2 - 2*(2*cos(3*b*x + a + 2*c)* cos(-a + c) - cos(b*x + a)*cos(-a + c))*cos(5*b*x + a + 4*c) - 2*(2*cos...
Leaf count of result is larger than twice the leaf count of optimal. 963 vs. \(2 (69) = 138\).
Time = 0.38 (sec) , antiderivative size = 963, normalized size of antiderivative = 13.19 \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\text {Too large to display} \]
1/8*(12*(tan(1/2*a)^2*tan(1/2*c)^3 - tan(1/2*a)^2*tan(1/2*c) + 4*tan(1/2*a )*tan(1/2*c)^2 - tan(1/2*c)^3 + tan(1/2*c))*log(abs(tan(1/2*b*x)*tan(1/2*c ) - 1))/(tan(1/2*a)^2*tan(1/2*c)^3 + tan(1/2*a)^2*tan(1/2*c) + tan(1/2*c)^ 3 + tan(1/2*c)) - 12*(tan(1/2*a)^2*tan(1/2*c)^2 - tan(1/2*a)^2 + 4*tan(1/2 *a)*tan(1/2*c) - tan(1/2*c)^2 + 1)*log(abs(tan(1/2*b*x) + tan(1/2*c)))/(ta n(1/2*a)^2*tan(1/2*c)^2 + tan(1/2*a)^2 + tan(1/2*c)^2 + 1) + 16*(2*tan(1/2 *b*x)*tan(1/2*a) + tan(1/2*a)^2 - 1)/((tan(1/2*b*x)^2 + 1)*(tan(1/2*a)^2 + 1)) + (2*tan(1/2*b*x)^3*tan(1/2*a)^2*tan(1/2*c)^7 + tan(1/2*b*x)^2*tan(1/ 2*a)^2*tan(1/2*c)^8 + 6*tan(1/2*b*x)^3*tan(1/2*a)^2*tan(1/2*c)^5 + 2*tan(1 /2*b*x)^2*tan(1/2*a)^2*tan(1/2*c)^6 - 2*tan(1/2*b*x)^3*tan(1/2*c)^7 - 4*ta n(1/2*b*x)^2*tan(1/2*a)*tan(1/2*c)^7 - 2*tan(1/2*b*x)*tan(1/2*a)^2*tan(1/2 *c)^7 - tan(1/2*b*x)^2*tan(1/2*c)^8 - 6*tan(1/2*b*x)^3*tan(1/2*a)^2*tan(1/ 2*c)^3 + 16*tan(1/2*b*x)^3*tan(1/2*a)*tan(1/2*c)^4 - 22*tan(1/2*b*x)^2*tan (1/2*a)^2*tan(1/2*c)^4 - 6*tan(1/2*b*x)^3*tan(1/2*c)^5 + 20*tan(1/2*b*x)^2 *tan(1/2*a)*tan(1/2*c)^5 - 14*tan(1/2*b*x)*tan(1/2*a)^2*tan(1/2*c)^5 - 2*t an(1/2*b*x)^2*tan(1/2*c)^6 + 16*tan(1/2*b*x)*tan(1/2*a)*tan(1/2*c)^6 + 2*t an(1/2*a)^2*tan(1/2*c)^6 + 2*tan(1/2*b*x)*tan(1/2*c)^7 - 2*tan(1/2*b*x)^3* tan(1/2*a)^2*tan(1/2*c) + 2*tan(1/2*b*x)^2*tan(1/2*a)^2*tan(1/2*c)^2 + 6*t an(1/2*b*x)^3*tan(1/2*c)^3 - 20*tan(1/2*b*x)^2*tan(1/2*a)*tan(1/2*c)^3 + 1 4*tan(1/2*b*x)*tan(1/2*a)^2*tan(1/2*c)^3 + 22*tan(1/2*b*x)^2*tan(1/2*c)...
Timed out. \[ \int \cos (a+b x) \cot ^3(c+b x) \, dx=\text {Hanged} \]